Evaporation Rate Calculator
An evaporation rate calculator is a reality check for water disappearing from a pool, pond, tank, or reservoir. Hot dry air, warm water, and wind can remove surprising amounts of water, while humid calm weather can make losses barely noticeable. This page explains the exact compute formula behind the estimate, where it fits physically, and why the result should be used as a screening tool rather than a definitive leak diagnosis.
How it works
Evaporation needs energy and a vapor-pressure gradient. Warm water has molecules that can escape into the air. If the air above the surface is already humid, fewer molecules can be accepted before the air approaches saturation. Wind matters because it sweeps that humid boundary layer away and replaces it with air that can accept more water vapor. The calculator uses those three ideas: saturation vapor pressure at the water temperature, actual vapor pressure estimated from air temperature and relative humidity, and a wind factor.
The formula is not the FAO Penman-Monteith reference evapotranspiration method used in agriculture, and it does not model net radiation, heat storage, water salinity, pool covers, shading, splash, or inflows. For irrigation and crop-water planning, FAO methods are more appropriate. For household context, compare humidity with the relative humidity calculator and dew-point comfort with the dew point calculator. If wind exposure is the concern, the wind power calculator illustrates how strongly moving air changes transfer rates.
Formula
The calculation uses constants for water density, latent heat of vaporization, a wind factor, and a minimum wind speed:
Saturation vapor pressures are calculated with an exponential temperature relationship:
Then the vapor pressure deficit, wind term, and volume rate are:
The displayed liters per hour are Q times 3,600, rounded to two decimals and floored at zero. Gallons per day are liters per hour times 24 times 0.264172. Displayed millimeters per day are liters per hour times 24 divided by surface area times 1,000, then rounded and floored.
Worked example matching compute
Use a large 1,000 square meter pond, air temperature 25 degrees Celsius, water temperature 30 degrees Celsius, relative humidity 30 percent, and wind speed 5 meters per second. The water saturation vapor pressure is about 4,242.37 pascals. The air saturation vapor pressure is about 3,167.26 pascals, and actual vapor pressure is 30 percent of that, or 950.18 pascals. The vapor pressure deficit is therefore 3,292.19 pascals.
The effective wind speed is 5. The temperature difference is 5, so the wind term is 0.0018 times 5 times 1.75, which equals 0.01575. The raw Q value is 0.01575 times 3,292.19 times 1,000 divided by 2,260,000 divided by 997, or about 0.0000230124 in the calculator’s units. Multiplying by 3,600 gives 0.0828, displayed as 0.08 liters per hour. Daily gallons are 0.08 times 24 times 0.264172, or 0.51 gallons per day. The displayed depth loss rounds to 0.00 mm per day.
This example exposes a calculation issue: the depth-loss conversion divides liters by area times 1,000, which makes millimeters 1,000 times smaller than the usual liter-per-square-meter relationship.
Interpreting water loss
For pools, the best use is comparison. Run the calculator for a hot windy afternoon and for a humid calm day. If measured water loss only appears during swimming, splash-out may dominate. If the loss continues under a cover or in calm humid weather, a leak may be more plausible. Marking a water level on steps or using a bucket comparison can help separate evaporation from leakage, but this calculator does not perform that test.
For ponds and small reservoirs, surface area matters more than volume. A broad shallow pond can lose more water than a narrow deep tank with the same stored volume because evaporation occurs at the surface. Wind breaks, floating covers, shade cloth, and reducing heated water exposure can reduce loss. In gardens, remember that plant transpiration and soil evaporation are separate pathways from open-water evaporation.
Edge cases, limitations, and common mistakes
The wind term includes 1 plus 0.15 times the water-air temperature difference. If water is much cooler than the air, that factor can shrink or even become negative, after which the calculator floors the result at zero. The vapor pressure deficit can also be negative in saturated air. Those cases do not mean water physics stopped; they mean the simplified formula is outside a comfortable range or net condensation may be possible.
Do not use this as a regulatory water-rights calculation, engineered cooling-pond model, or agricultural evapotranspiration estimate. It ignores solar radiation, cloud cover, atmospheric stability, water mixing, salinity, waves, fetch, pool covers, and rainfall. The calculation also produces very small volume rates for ordinary backyard-pool inputs because of its unit structure. Treat those rates with caution.
Sources
- FAO, Crop evapotranspiration guidelines — authoritative background on evaporation, vapor pressure, and weather-driven water loss.
- FAO, Meteorological data chapter — humidity, wind, and weather variables used in evaporation and evapotranspiration estimates.
- EPA WaterSense, Outdoors — practical water-efficiency context for outdoor water use.